2(z+2)=4(z-2)

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Solution for 2(z+2)=4(z-2) equation: 



2(z+2)=4(z-2)

We move all terms to the left:

2(z+2)-(4(z-2))=0

We multiply parentheses

2z-(4(z-2))+4=0



We calculate terms in parentheses: -(4(z-2)), so:

4(z-2)

We multiply parentheses

4z-8

Back to the equation:

-(4z-8)



We get rid of parentheses

2z-4z+8+4=0

We add all the numbers together, and all the variables

-2z+12=0

We move all terms containing z to the left, all other terms to the right

-2z=-12

z=-12/-2

z=+6

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