2(z+2)=5z+4-3z

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Solution for 2(z+2)=5z+4-3z equation:


Simplifying
2(z + 2) = 5z + 4 + -3z

Reorder the terms:
2(2 + z) = 5z + 4 + -3z
(2 * 2 + z * 2) = 5z + 4 + -3z
(4 + 2z) = 5z + 4 + -3z

Reorder the terms:
4 + 2z = 4 + 5z + -3z

Combine like terms: 5z + -3z = 2z
4 + 2z = 4 + 2z

Add '-4' to each side of the equation.
4 + -4 + 2z = 4 + -4 + 2z

Combine like terms: 4 + -4 = 0
0 + 2z = 4 + -4 + 2z
2z = 4 + -4 + 2z

Combine like terms: 4 + -4 = 0
2z = 0 + 2z
2z = 2z

Add '-2z' to each side of the equation.
2z + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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