2(z+2)=7(z-2)-2

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Solution for 2(z+2)=7(z-2)-2 equation:


Simplifying
2(z + 2) = 7(z + -2) + -2

Reorder the terms:
2(2 + z) = 7(z + -2) + -2
(2 * 2 + z * 2) = 7(z + -2) + -2
(4 + 2z) = 7(z + -2) + -2

Reorder the terms:
4 + 2z = 7(-2 + z) + -2
4 + 2z = (-2 * 7 + z * 7) + -2
4 + 2z = (-14 + 7z) + -2

Reorder the terms:
4 + 2z = -14 + -2 + 7z

Combine like terms: -14 + -2 = -16
4 + 2z = -16 + 7z

Solving
4 + 2z = -16 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
4 + 2z + -7z = -16 + 7z + -7z

Combine like terms: 2z + -7z = -5z
4 + -5z = -16 + 7z + -7z

Combine like terms: 7z + -7z = 0
4 + -5z = -16 + 0
4 + -5z = -16

Add '-4' to each side of the equation.
4 + -4 + -5z = -16 + -4

Combine like terms: 4 + -4 = 0
0 + -5z = -16 + -4
-5z = -16 + -4

Combine like terms: -16 + -4 = -20
-5z = -20

Divide each side by '-5'.
z = 4

Simplifying
z = 4

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