2(z+3)+4(z+2)=

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Solution for 2(z+3)+4(z+2)= equation:


Simplifying
2(z + 3) + 4(z + 2) = 0

Reorder the terms:
2(3 + z) + 4(z + 2) = 0
(3 * 2 + z * 2) + 4(z + 2) = 0
(6 + 2z) + 4(z + 2) = 0

Reorder the terms:
6 + 2z + 4(2 + z) = 0
6 + 2z + (2 * 4 + z * 4) = 0
6 + 2z + (8 + 4z) = 0

Reorder the terms:
6 + 8 + 2z + 4z = 0

Combine like terms: 6 + 8 = 14
14 + 2z + 4z = 0

Combine like terms: 2z + 4z = 6z
14 + 6z = 0

Solving
14 + 6z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 6z = 0 + -14

Combine like terms: 14 + -14 = 0
0 + 6z = 0 + -14
6z = 0 + -14

Combine like terms: 0 + -14 = -14
6z = -14

Divide each side by '6'.
z = -2.333333333

Simplifying
z = -2.333333333

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