2(z+3)-z=-2-4(z+2)

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Solution for 2(z+3)-z=-2-4(z+2) equation: 



2(z+3)-z=-2-4(z+2)

We move all terms to the left:

2(z+3)-z-(-2-4(z+2))=0

We add all the numbers together, and all the variables

-1z+2(z+3)-(-2-4(z+2))=0

We multiply parentheses

-1z+2z-(-2-4(z+2))+6=0



We calculate terms in parentheses: -(-2-4(z+2)), so:

-2-4(z+2)

determiningTheFunctionDomain
-4(z+2)-2

We multiply parentheses

-4z-8-2

We add all the numbers together, and all the variables

-4z-10

Back to the equation:

-(-4z-10)



We add all the numbers together, and all the variables

z-(-4z-10)+6=0

We get rid of parentheses

z+4z+10+6=0

We add all the numbers together, and all the variables

5z+16=0

We move all terms containing z to the left, all other terms to the right

5z=-16

z=-16/5

z=-3+1/5

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