2(z+4)=4(2z-1)

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Solution for 2(z+4)=4(2z-1) equation: 



2(z+4)=4(2z-1)

We move all terms to the left:

2(z+4)-(4(2z-1))=0

We multiply parentheses

2z-(4(2z-1))+8=0



We calculate terms in parentheses: -(4(2z-1)), so:

4(2z-1)

We multiply parentheses

8z-4

Back to the equation:

-(8z-4)



We get rid of parentheses

2z-8z+4+8=0

We add all the numbers together, and all the variables

-6z+12=0

We move all terms containing z to the left, all other terms to the right

-6z=-12

z=-12/-6

z=+2

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