2(z+4)=4+2(1-5z)

Solution for 2(z+4)=4+2(1-5z) equation:

2(z+4)=4+2(1-5z)

We move all terms to the left:

2(z+4)-(4+2(1-5z))=0

We add all the numbers together, and all the variables

2(z+4)-(4+2(-5z+1))=0

We multiply parentheses

2z-(4+2(-5z+1))+8=0


We calculate terms in parentheses: -(4+2(-5z+1)), so:

4+2(-5z+1)

determiningTheFunctionDomain
2(-5z+1)+4

We multiply parentheses

-10z+2+4

We add all the numbers together, and all the variables

-10z+6

Back to the equation:

-(-10z+6)


We get rid of parentheses

2z+10z-6+8=0

We add all the numbers together, and all the variables

12z+2=0

We move all terms containing z to the left, all other terms to the right

12z=-2

z=-2/12

z=-1/6