2(z+7)+3z-5=28

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Solution for 2(z+7)+3z-5=28 equation: 



2(z+7)+3z-5=28

We move all terms to the left:

2(z+7)+3z-5-(28)=0

We add all the numbers together, and all the variables

3z+2(z+7)-33=0

We multiply parentheses

3z+2z+14-33=0

We add all the numbers together, and all the variables

5z-19=0

We move all terms containing z to the left, all other terms to the right

5z=19

z=19/5

z=3+4/5

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