2(z-1)+3(z-4)=5

Solution for 2(z-1)+3(z-4)=5 equation:

Simplifying
2(z + -1) + 3(z + -4) = 5

Reorder the terms:
2(-1 + z) + 3(z + -4) = 5
(-1 * 2 + z * 2) + 3(z + -4) = 5
(-2 + 2z) + 3(z + -4) = 5

Reorder the terms:
-2 + 2z + 3(-4 + z) = 5
-2 + 2z + (-4 * 3 + z * 3) = 5
-2 + 2z + (-12 + 3z) = 5

Reorder the terms:
-2 + -12 + 2z + 3z = 5

Combine like terms: -2 + -12 = -14
-14 + 2z + 3z = 5

Combine like terms: 2z + 3z = 5z
-14 + 5z = 5

Solving
-14 + 5z = 5

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 5z = 5 + 14

Combine like terms: -14 + 14 = 0
0 + 5z = 5 + 14
5z = 5 + 14

Combine like terms: 5 + 14 = 19
5z = 19

Divide each side by '5'.
z = 3.8

Simplifying
z = 3.8