2(z-1)-3(z-2)=12

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Solution for 2(z-1)-3(z-2)=12 equation:


Simplifying
2(z + -1) + -3(z + -2) = 12

Reorder the terms:
2(-1 + z) + -3(z + -2) = 12
(-1 * 2 + z * 2) + -3(z + -2) = 12
(-2 + 2z) + -3(z + -2) = 12

Reorder the terms:
-2 + 2z + -3(-2 + z) = 12
-2 + 2z + (-2 * -3 + z * -3) = 12
-2 + 2z + (6 + -3z) = 12

Reorder the terms:
-2 + 6 + 2z + -3z = 12

Combine like terms: -2 + 6 = 4
4 + 2z + -3z = 12

Combine like terms: 2z + -3z = -1z
4 + -1z = 12

Solving
4 + -1z = 12

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1z = 12 + -4

Combine like terms: 4 + -4 = 0
0 + -1z = 12 + -4
-1z = 12 + -4

Combine like terms: 12 + -4 = 8
-1z = 8

Divide each side by '-1'.
z = -8

Simplifying
z = -8

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