2(z-1)-6=10(1-x)+6

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Solution for 2(z-1)-6=10(1-x)+6 equation: 


Simplifying
2(z + -1) + -6 = 10(1 + -1x) + 6

Reorder the terms:
2(-1 + z) + -6 = 10(1 + -1x) + 6
(-1 * 2 + z * 2) + -6 = 10(1 + -1x) + 6
(-2 + 2z) + -6 = 10(1 + -1x) + 6

Reorder the terms:
-2 + -6 + 2z = 10(1 + -1x) + 6

Combine like terms: -2 + -6 = -8
-8 + 2z = 10(1 + -1x) + 6
-8 + 2z = (1 * 10 + -1x * 10) + 6
-8 + 2z = (10 + -10x) + 6

Reorder the terms:
-8 + 2z = 10 + 6 + -10x

Combine like terms: 10 + 6 = 16
-8 + 2z = 16 + -10x

Solving
-8 + 2z = 16 + -10x

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 2z = 16 + 8 + -10x

Combine like terms: -8 + 8 = 0
0 + 2z = 16 + 8 + -10x
2z = 16 + 8 + -10x

Combine like terms: 16 + 8 = 24
2z = 24 + -10x

Divide each side by '2'.
z = 12 + -5x

Simplifying
z = 12 + -5x

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