2(z-1)=3+2

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Solution for 2(z-1)=3+2 equation: 



2(z-1)=3+2

We move all terms to the left:

2(z-1)-(3+2)=0

We add all the numbers together, and all the variables

2(z-1)-5=0

We multiply parentheses

2z-2-5=0

We add all the numbers together, and all the variables

2z-7=0

We move all terms containing z to the left, all other terms to the right

2z=7

z=7/2

z=3+1/2

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