2(z-12)-1=z-25+z

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Solution for 2(z-12)-1=z-25+z equation:


Simplifying
2(z + -12) + -1 = z + -25 + z

Reorder the terms:
2(-12 + z) + -1 = z + -25 + z
(-12 * 2 + z * 2) + -1 = z + -25 + z
(-24 + 2z) + -1 = z + -25 + z

Reorder the terms:
-24 + -1 + 2z = z + -25 + z

Combine like terms: -24 + -1 = -25
-25 + 2z = z + -25 + z

Reorder the terms:
-25 + 2z = -25 + z + z

Combine like terms: z + z = 2z
-25 + 2z = -25 + 2z

Add '25' to each side of the equation.
-25 + 25 + 2z = -25 + 25 + 2z

Combine like terms: -25 + 25 = 0
0 + 2z = -25 + 25 + 2z
2z = -25 + 25 + 2z

Combine like terms: -25 + 25 = 0
2z = 0 + 2z
2z = 2z

Add '-2z' to each side of the equation.
2z + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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