2(z-21)+4(z-4)=56

Solution for 2(z-21)+4(z-4)=56 equation:

Simplifying
2(z + -21) + 4(z + -4) = 56

Reorder the terms:
2(-21 + z) + 4(z + -4) = 56
(-21 * 2 + z * 2) + 4(z + -4) = 56
(-42 + 2z) + 4(z + -4) = 56

Reorder the terms:
-42 + 2z + 4(-4 + z) = 56
-42 + 2z + (-4 * 4 + z * 4) = 56
-42 + 2z + (-16 + 4z) = 56

Reorder the terms:
-42 + -16 + 2z + 4z = 56

Combine like terms: -42 + -16 = -58
-58 + 2z + 4z = 56

Combine like terms: 2z + 4z = 6z
-58 + 6z = 56

Solving
-58 + 6z = 56

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '58' to each side of the equation.
-58 + 58 + 6z = 56 + 58

Combine like terms: -58 + 58 = 0
0 + 6z = 56 + 58
6z = 56 + 58

Combine like terms: 56 + 58 = 114
6z = 114

Divide each side by '6'.
z = 19

Simplifying
z = 19