2(z-24)+4(z-4)=32

Solution for 2(z-24)+4(z-4)=32 equation:

Simplifying
2(z + -24) + 4(z + -4) = 32

Reorder the terms:
2(-24 + z) + 4(z + -4) = 32
(-24 * 2 + z * 2) + 4(z + -4) = 32
(-48 + 2z) + 4(z + -4) = 32

Reorder the terms:
-48 + 2z + 4(-4 + z) = 32
-48 + 2z + (-4 * 4 + z * 4) = 32
-48 + 2z + (-16 + 4z) = 32

Reorder the terms:
-48 + -16 + 2z + 4z = 32

Combine like terms: -48 + -16 = -64
-64 + 2z + 4z = 32

Combine like terms: 2z + 4z = 6z
-64 + 6z = 32

Solving
-64 + 6z = 32

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '64' to each side of the equation.
-64 + 64 + 6z = 32 + 64

Combine like terms: -64 + 64 = 0
0 + 6z = 32 + 64
6z = 32 + 64

Combine like terms: 32 + 64 = 96
6z = 96

Divide each side by '6'.
z = 16

Simplifying
z = 16