2(z-27)=z+3

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Solution for 2(z-27)=z+3 equation: 



2(z-27)=z+3

We move all terms to the left:

2(z-27)-(z+3)=0

We multiply parentheses

2z-(z+3)-54=0

We get rid of parentheses

2z-z-3-54=0

We add all the numbers together, and all the variables

z-57=0

We move all terms containing z to the left, all other terms to the right

z=57

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