2(z-3)+3z=7z+6

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Solution for 2(z-3)+3z=7z+6 equation:


Simplifying
2(z + -3) + 3z = 7z + 6

Reorder the terms:
2(-3 + z) + 3z = 7z + 6
(-3 * 2 + z * 2) + 3z = 7z + 6
(-6 + 2z) + 3z = 7z + 6

Combine like terms: 2z + 3z = 5z
-6 + 5z = 7z + 6

Reorder the terms:
-6 + 5z = 6 + 7z

Solving
-6 + 5z = 6 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-6 + 5z + -7z = 6 + 7z + -7z

Combine like terms: 5z + -7z = -2z
-6 + -2z = 6 + 7z + -7z

Combine like terms: 7z + -7z = 0
-6 + -2z = 6 + 0
-6 + -2z = 6

Add '6' to each side of the equation.
-6 + 6 + -2z = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -2z = 6 + 6
-2z = 6 + 6

Combine like terms: 6 + 6 = 12
-2z = 12

Divide each side by '-2'.
z = -6

Simplifying
z = -6

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