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2(z-3)+5=3(z-1)
We move all terms to the left:
2(z-3)+5-(3(z-1))=0
We multiply parentheses
2z-(3(z-1))-6+5=0
We calculate terms in parentheses: -(3(z-1)), so:We add all the numbers together, and all the variables
3(z-1)
We multiply parentheses
3z-3
Back to the equation:
-(3z-3)
2z-(3z-3)-1=0
We get rid of parentheses
2z-3z+3-1=0
We add all the numbers together, and all the variables
-1z+2=0
We move all terms containing z to the left, all other terms to the right
-z=-2
z=-2/-1
z=+2
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