2(z-3)+5=3(z-1)

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Solution for 2(z-3)+5=3(z-1) equation: 



2(z-3)+5=3(z-1)

We move all terms to the left:

2(z-3)+5-(3(z-1))=0

We multiply parentheses

2z-(3(z-1))-6+5=0



We calculate terms in parentheses: -(3(z-1)), so:

3(z-1)

We multiply parentheses

3z-3

Back to the equation:

-(3z-3)



We add all the numbers together, and all the variables

2z-(3z-3)-1=0

We get rid of parentheses

2z-3z+3-1=0

We add all the numbers together, and all the variables

-1z+2=0

We move all terms containing z to the left, all other terms to the right

-z=-2

z=-2/-1

z=+2

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