2(z-3)-(-9z-5)=10

Solution for 2(z-3)-(-9z-5)=10 equation:

Simplifying
2(z + -3) + -1(-9z + -5) = 10

Reorder the terms:
2(-3 + z) + -1(-9z + -5) = 10
(-3 * 2 + z * 2) + -1(-9z + -5) = 10
(-6 + 2z) + -1(-9z + -5) = 10

Reorder the terms:
-6 + 2z + -1(-5 + -9z) = 10
-6 + 2z + (-5 * -1 + -9z * -1) = 10
-6 + 2z + (5 + 9z) = 10

Reorder the terms:
-6 + 5 + 2z + 9z = 10

Combine like terms: -6 + 5 = -1
-1 + 2z + 9z = 10

Combine like terms: 2z + 9z = 11z
-1 + 11z = 10

Solving
-1 + 11z = 10

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 11z = 10 + 1

Combine like terms: -1 + 1 = 0
0 + 11z = 10 + 1
11z = 10 + 1

Combine like terms: 10 + 1 = 11
11z = 11

Divide each side by '11'.
z = 1

Simplifying
z = 1