2(z-3)=4(z+5)-14

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Solution for 2(z-3)=4(z+5)-14 equation:



2(z-3)=4(z+5)-14
We move all terms to the left:
2(z-3)-(4(z+5)-14)=0
We multiply parentheses
2z-(4(z+5)-14)-6=0
We calculate terms in parentheses: -(4(z+5)-14), so:
4(z+5)-14
We multiply parentheses
4z+20-14
We add all the numbers together, and all the variables
4z+6
Back to the equation:
-(4z+6)
We get rid of parentheses
2z-4z-6-6=0
We add all the numbers together, and all the variables
-2z-12=0
We move all terms containing z to the left, all other terms to the right
-2z=12
z=12/-2
z=-6

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