2(z-30)=68

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Solution for 2(z-30)=68 equation: 



2(z-30)=68

We move all terms to the left:

2(z-30)-(68)=0

We multiply parentheses

2z-60-68=0

We add all the numbers together, and all the variables

2z-128=0

We move all terms containing z to the left, all other terms to the right

2z=128

z=128/2

z=64

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