2(z-4)=4(z+1)

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Solution for 2(z-4)=4(z+1) equation:


Simplifying
2(z + -4) = 4(z + 1)

Reorder the terms:
2(-4 + z) = 4(z + 1)
(-4 * 2 + z * 2) = 4(z + 1)
(-8 + 2z) = 4(z + 1)

Reorder the terms:
-8 + 2z = 4(1 + z)
-8 + 2z = (1 * 4 + z * 4)
-8 + 2z = (4 + 4z)

Solving
-8 + 2z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-8 + 2z + -4z = 4 + 4z + -4z

Combine like terms: 2z + -4z = -2z
-8 + -2z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-8 + -2z = 4 + 0
-8 + -2z = 4

Add '8' to each side of the equation.
-8 + 8 + -2z = 4 + 8

Combine like terms: -8 + 8 = 0
0 + -2z = 4 + 8
-2z = 4 + 8

Combine like terms: 4 + 8 = 12
-2z = 12

Divide each side by '-2'.
z = -6

Simplifying
z = -6

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