2(z-4)=5(z+1)-7

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Solution for 2(z-4)=5(z+1)-7 equation:


2(z-4)=5(z+1)-7

We simplify the equation to the form, which is simple to understand
2(z-4)=5(z+1)-7

Reorder the terms in parentheses
+(+2z-8)=5*(z+1)-7

Remove unnecessary parentheses
+2z-8=+5+*(+z+1+)-7

Reorder the terms in parentheses
+2z-8=+(+5z+5)-7

Remove unnecessary parentheses
+2z-8=+5z+5-7

We move all terms containing z to the left and all other terms to the right.
+2z-5z=+5-7+8

We simplify left and right side of the equation.
-3z=+6

We divide both sides of the equation by -3 to get z.
z=-2

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