2(z-4)=5(z+6)-17

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Solution for 2(z-4)=5(z+6)-17 equation: 



2(z-4)=5(z+6)-17

We move all terms to the left:

2(z-4)-(5(z+6)-17)=0

We multiply parentheses

2z-(5(z+6)-17)-8=0



We calculate terms in parentheses: -(5(z+6)-17), so:

5(z+6)-17

We multiply parentheses

5z+30-17

We add all the numbers together, and all the variables

5z+13

Back to the equation:

-(5z+13)



We get rid of parentheses

2z-5z-13-8=0

We add all the numbers together, and all the variables

-3z-21=0

We move all terms containing z to the left, all other terms to the right

-3z=21

z=21/-3

z=-7

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