2(z-4)=6z+8

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Solution for 2(z-4)=6z+8 equation: 



2(z-4)=6z+8

We move all terms to the left:

2(z-4)-(6z+8)=0

We multiply parentheses

2z-(6z+8)-8=0

We get rid of parentheses

2z-6z-8-8=0

We add all the numbers together, and all the variables

-4z-16=0

We move all terms containing z to the left, all other terms to the right

-4z=16

z=16/-4

z=-4

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