2(z-4)=9(5+z)

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Solution for 2(z-4)=9(5+z) equation: 



2(z-4)=9(5+z)

We move all terms to the left:

2(z-4)-(9(5+z))=0

We add all the numbers together, and all the variables

2(z-4)-(9(z+5))=0

We multiply parentheses

2z-(9(z+5))-8=0



We calculate terms in parentheses: -(9(z+5)), so:

9(z+5)

We multiply parentheses

9z+45

Back to the equation:

-(9z+45)



We get rid of parentheses

2z-9z-45-8=0

We add all the numbers together, and all the variables

-7z-53=0

We move all terms containing z to the left, all other terms to the right

-7z=53

z=53/-7

z=-7+4/7

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