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2(z-5)+12=5z-3(z-10)
We move all terms to the left:
2(z-5)+12-(5z-3(z-10))=0
We multiply parentheses
2z-(5z-3(z-10))-10+12=0
We calculate terms in parentheses: -(5z-3(z-10)), so:We add all the numbers together, and all the variables
5z-3(z-10)
We multiply parentheses
5z-3z+30
We add all the numbers together, and all the variables
2z+30
Back to the equation:
-(2z+30)
2z-(2z+30)+2=0
We get rid of parentheses
2z-2z-30+2=0
We add all the numbers together, and all the variables
-28!=0
There is no solution for this equation
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