2(z-6)+-5=3

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Solution for 2(z-6)+-5=3 equation:



2(z-6)+-5=3
We move all terms to the left:
2(z-6)+-5-(3)=0
determiningTheFunctionDomain 2(z-6)-5-3+=0
We add all the numbers together, and all the variables
2(z-6)=0
We multiply parentheses
2z-12=0
We move all terms containing z to the left, all other terms to the right
2z=12
z=12/2
z=6

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