2(z-8)+7=5(z+2)-3z-19

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Solution for 2(z-8)+7=5(z+2)-3z-19 equation:


Simplifying
2(z + -8) + 7 = 5(z + 2) + -3z + -19

Reorder the terms:
2(-8 + z) + 7 = 5(z + 2) + -3z + -19
(-8 * 2 + z * 2) + 7 = 5(z + 2) + -3z + -19
(-16 + 2z) + 7 = 5(z + 2) + -3z + -19

Reorder the terms:
-16 + 7 + 2z = 5(z + 2) + -3z + -19

Combine like terms: -16 + 7 = -9
-9 + 2z = 5(z + 2) + -3z + -19

Reorder the terms:
-9 + 2z = 5(2 + z) + -3z + -19
-9 + 2z = (2 * 5 + z * 5) + -3z + -19
-9 + 2z = (10 + 5z) + -3z + -19

Reorder the terms:
-9 + 2z = 10 + -19 + 5z + -3z

Combine like terms: 10 + -19 = -9
-9 + 2z = -9 + 5z + -3z

Combine like terms: 5z + -3z = 2z
-9 + 2z = -9 + 2z

Add '9' to each side of the equation.
-9 + 9 + 2z = -9 + 9 + 2z

Combine like terms: -9 + 9 = 0
0 + 2z = -9 + 9 + 2z
2z = -9 + 9 + 2z

Combine like terms: -9 + 9 = 0
2z = 0 + 2z
2z = 2z

Add '-2z' to each side of the equation.
2z + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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