2*(1+z)+3*(7-z)-4*(2z-1)-(6-12z)=0

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Solution for 2*(1+z)+3*(7-z)-4*(2z-1)-(6-12z)=0 equation: 



2(1+z)+3(7-z)-4(2z-1)-(6-12z)=0

We add all the numbers together, and all the variables

2(z+1)+3(-1z+7)-4(2z-1)-(-12z+6)=0

We multiply parentheses

2z-3z-8z-(-12z+6)+2+21+4=0

We get rid of parentheses

2z-3z-8z+12z-6+2+21+4=0

We add all the numbers together, and all the variables

3z+21=0

We move all terms containing z to the left, all other terms to the right

3z=-21

z=-21/3

z=-7

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