2*(3x+5)-(6x-37)=(2x+15)

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Solution for 2*(3x+5)-(6x-37)=(2x+15) equation: 



2(3x+5)-(6x-37)=(2x+15)

We move all terms to the left:

2(3x+5)-(6x-37)-((2x+15))=0

We multiply parentheses

6x-(6x-37)-((2x+15))+10=0

We get rid of parentheses

6x-6x-((2x+15))+37+10=0



We calculate terms in parentheses: -((2x+15)), so:

(2x+15)

We get rid of parentheses

2x+15

Back to the equation:

-(2x+15)



We add all the numbers together, and all the variables

-(2x+15)+47=0

We get rid of parentheses

-2x-15+47=0

We add all the numbers together, and all the variables

-2x+32=0

We move all terms containing x to the left, all other terms to the right

-2x=-32

x=-32/-2

x=+16

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