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2(3x-12)=(8-4x)/4
We move all terms to the left:
2(3x-12)-((8-4x)/4)=0
We add all the numbers together, and all the variables
2(3x-12)-((-4x+8)/4)=0
We multiply parentheses
6x-((-4x+8)/4)-24=0
We multiply all the terms by the denominator
6x*4)-((-4x+8)-24*4)=0
We add all the numbers together, and all the variables
6x*4)-((-4x+8)=0
Wy multiply elements
24x^2=0
a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{48}=0$
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