2*(3x-2)-4x=3*(x-4)

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Solution for 2*(3x-2)-4x=3*(x-4) equation: 



2(3x-2)-4x=3(x-4)

We move all terms to the left:

2(3x-2)-4x-(3(x-4))=0

We add all the numbers together, and all the variables

-4x+2(3x-2)-(3(x-4))=0

We multiply parentheses

-4x+6x-(3(x-4))-4=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

2x-(3x-12)-4=0

We get rid of parentheses

2x-3x+12-4=0

We add all the numbers together, and all the variables

-1x+8=0

We move all terms containing x to the left, all other terms to the right

-x=-8

x=-8/-1

x=+8

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