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2(3x-4)+5=2(2+4x)-5
We move all terms to the left:
2(3x-4)+5-(2(2+4x)-5)=0
We add all the numbers together, and all the variables
2(3x-4)-(2(4x+2)-5)+5=0
We multiply parentheses
6x-(2(4x+2)-5)-8+5=0
We calculate terms in parentheses: -(2(4x+2)-5), so:We add all the numbers together, and all the variables
2(4x+2)-5
We multiply parentheses
8x+4-5
We add all the numbers together, and all the variables
8x-1
Back to the equation:
-(8x-1)
6x-(8x-1)-3=0
We get rid of parentheses
6x-8x+1-3=0
We add all the numbers together, and all the variables
-2x-2=0
We move all terms containing x to the left, all other terms to the right
-2x=2
x=2/-2
x=-1
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