2*(3x-4)-3*(2-3x)=8+(4x-4)

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Solution for 2*(3x-4)-3*(2-3x)=8+(4x-4) equation: 



2(3x-4)-3(2-3x)=8+(4x-4)

We move all terms to the left:

2(3x-4)-3(2-3x)-(8+(4x-4))=0

We add all the numbers together, and all the variables

2(3x-4)-3(-3x+2)-(8+(4x-4))=0

We multiply parentheses

6x+9x-(8+(4x-4))-8-6=0



We calculate terms in parentheses: -(8+(4x-4)), so:

8+(4x-4)

determiningTheFunctionDomain
(4x-4)+8

We get rid of parentheses

4x-4+8

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

15x-(4x+4)-14=0

We get rid of parentheses

15x-4x-4-14=0

We add all the numbers together, and all the variables

11x-18=0

We move all terms containing x to the left, all other terms to the right

11x=18

x=18/11

x=1+7/11

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