2*(3x-4*(6x-(x-1)-3)-2)=-(x-3)

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Solution for 2*(3x-4*(6x-(x-1)-3)-2)=-(x-3) equation: 



2(3x-4(6x-(x-1)-3)-2)=-(x-3)

We move all terms to the left:

2(3x-4(6x-(x-1)-3)-2)-(-(x-3))=0



We calculate terms in parentheses: -(-(x-3)), so:

-(x-3)

We get rid of parentheses

-x+3

We add all the numbers together, and all the variables

-1x+3

Back to the equation:

-(-1x+3)



We get rid of parentheses

2(3x-4(6x-(x-1)-3)-2)+1x-3=0

We add all the numbers together, and all the variables

x+2(3x-4(6x-(x-1)-3)-2)-3=0

We move all terms containing x to the left, all other terms to the right

x+2(3x-4(6x-(x-1)-3)-2)=3

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