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2(4x+5)-5x=4-3(x-5)
We move all terms to the left:
2(4x+5)-5x-(4-3(x-5))=0
We add all the numbers together, and all the variables
-5x+2(4x+5)-(4-3(x-5))=0
We multiply parentheses
-5x+8x-(4-3(x-5))+10=0
We calculate terms in parentheses: -(4-3(x-5)), so:We add all the numbers together, and all the variables
4-3(x-5)
determiningTheFunctionDomain -3(x-5)+4
We multiply parentheses
-3x+15+4
We add all the numbers together, and all the variables
-3x+19
Back to the equation:
-(-3x+19)
3x-(-3x+19)+10=0
We get rid of parentheses
3x+3x-19+10=0
We add all the numbers together, and all the variables
6x-9=0
We move all terms containing x to the left, all other terms to the right
6x=9
x=9/6
x=1+1/2
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