2*(7*x-5)-(2*t-3)*4=0

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Solution for 2*(7*x-5)-(2*t-3)*4=0 equation:


Simplifying
2(7x + -5) + -1(2t + -3) * 4 = 0

Reorder the terms:
2(-5 + 7x) + -1(2t + -3) * 4 = 0
(-5 * 2 + 7x * 2) + -1(2t + -3) * 4 = 0
(-10 + 14x) + -1(2t + -3) * 4 = 0

Reorder the terms:
-10 + 14x + -1(-3 + 2t) * 4 = 0

Reorder the terms for easier multiplication:
-10 + 14x + -1 * 4(-3 + 2t) = 0

Multiply -1 * 4
-10 + 14x + -4(-3 + 2t) = 0
-10 + 14x + (-3 * -4 + 2t * -4) = 0
-10 + 14x + (12 + -8t) = 0

Reorder the terms:
-10 + 12 + -8t + 14x = 0

Combine like terms: -10 + 12 = 2
2 + -8t + 14x = 0

Solving
2 + -8t + 14x = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -8t + -2 + 14x = 0 + -2

Reorder the terms:
2 + -2 + -8t + 14x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -8t + 14x = 0 + -2
-8t + 14x = 0 + -2

Combine like terms: 0 + -2 = -2
-8t + 14x = -2

Add '-14x' to each side of the equation.
-8t + 14x + -14x = -2 + -14x

Combine like terms: 14x + -14x = 0
-8t + 0 = -2 + -14x
-8t = -2 + -14x

Divide each side by '-8'.
t = 0.25 + 1.75x

Simplifying
t = 0.25 + 1.75x

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