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2(x)(10-2x)+2(x)(16-2x)=144
We move all terms to the left:
2(x)(10-2x)+2(x)(16-2x)-(144)=0
We add all the numbers together, and all the variables
2x(-2x+10)+2x(-2x+16)-144=0
We multiply parentheses
-4x^2-4x^2+20x+32x-144=0
We add all the numbers together, and all the variables
-8x^2+52x-144=0
a = -8; b = 52; c = -144;
Δ = b2-4ac
Δ = 522-4·(-8)·(-144)
Δ = -1904
Delta is less than zero, so there is no solution for the equation
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