2*(x+1)*(x+1)=72

Solution for 2*(x+1)*(x+1)=72 equation:

2(x+1)(x+1)=72

We move all terms to the left:

2(x+1)(x+1)-(72)=0

We multiply parentheses ..

2(+x^2+x+x+1)-72=0

We multiply parentheses

2x^2+2x+2x+2-72=0

We add all the numbers together, and all the variables

2x^2+4x-70=0

a = 2; b = 4; c = -70;
Δ = b2-4ac
Δ = 42-4·2·(-70)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-24}{2*2}=\frac{-28}{4}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+24}{2*2}=\frac{20}{4}
=5
$