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2(x-3)(4x+7)=0
We multiply parentheses ..
2(+4x^2+7x-12x-21)=0
We multiply parentheses
8x^2+14x-24x-42=0
We add all the numbers together, and all the variables
8x^2-10x-42=0
a = 8; b = -10; c = -42;
Δ = b2-4ac
Δ = -102-4·8·(-42)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-38}{2*8}=\frac{-28}{16} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+38}{2*8}=\frac{48}{16} =3 $
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