2*(x-3)*(x+3)=0

Solution for 2*(x-3)*(x+3)=0 equation:

Simplifying
2(x + -3)(x + 3) = 0

Reorder the terms:
2(-3 + x)(x + 3) = 0

Reorder the terms:
2(-3 + x)(3 + x) = 0

Multiply (-3 + x) * (3 + x)
2(-3(3 + x) + x(3 + x)) = 0
2((3 * -3 + x * -3) + x(3 + x)) = 0
2((-9 + -3x) + x(3 + x)) = 0
2(-9 + -3x + (3 * x + x * x)) = 0
2(-9 + -3x + (3x + x2)) = 0

Combine like terms: -3x + 3x = 0
2(-9 + 0 + x2) = 0
2(-9 + x2) = 0
(-9 * 2 + x2 * 2) = 0
(-18 + 2x2) = 0

Solving
-18 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '18' to each side of the equation.
-18 + 18 + 2x2 = 0 + 18

Combine like terms: -18 + 18 = 0
0 + 2x2 = 0 + 18
2x2 = 0 + 18

Combine like terms: 0 + 18 = 18
2x2 = 18

Divide each side by '2'.
x2 = 9

Simplifying
x2 = 9

Take the square root of each side:
x = {-3, 3}