2*(x-3)+2-3x=x-4*(x-1)

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Solution for 2*(x-3)+2-3x=x-4*(x-1) equation: 



2(x-3)+2-3x=x-4(x-1)

We move all terms to the left:

2(x-3)+2-3x-(x-4(x-1))=0

We add all the numbers together, and all the variables

-3x+2(x-3)-(x-4(x-1))+2=0

We multiply parentheses

-3x+2x-(x-4(x-1))-6+2=0



We calculate terms in parentheses: -(x-4(x-1)), so:

x-4(x-1)

We multiply parentheses

x-4x+4

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We add all the numbers together, and all the variables

-1x-(-3x+4)-4=0

We get rid of parentheses

-1x+3x-4-4=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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