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2(x-3)+2=4(2x-1)
We move all terms to the left:
2(x-3)+2-(4(2x-1))=0
We multiply parentheses
2x-(4(2x-1))-6+2=0
We calculate terms in parentheses: -(4(2x-1)), so:We add all the numbers together, and all the variables
4(2x-1)
We multiply parentheses
8x-4
Back to the equation:
-(8x-4)
2x-(8x-4)-4=0
We get rid of parentheses
2x-8x+4-4=0
We add all the numbers together, and all the variables
-6x=0
x=0/-6
x=0
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