2*(x-3)=3*(x-2)

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Solution for 2*(x-3)=3*(x-2) equation: 



2(x-3)=3(x-2)

We move all terms to the left:

2(x-3)-(3(x-2))=0

We multiply parentheses

2x-(3(x-2))-6=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

2x-3x+6-6=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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