2*(x-5)+3(x-2)=8+7(x-4)

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Solution for 2*(x-5)+3(x-2)=8+7(x-4) equation: 



2(x-5)+3(x-2)=8+7(x-4)

We move all terms to the left:

2(x-5)+3(x-2)-(8+7(x-4))=0

We multiply parentheses

2x+3x-(8+7(x-4))-10-6=0



We calculate terms in parentheses: -(8+7(x-4)), so:

8+7(x-4)

determiningTheFunctionDomain
7(x-4)+8

We multiply parentheses

7x-28+8

We add all the numbers together, and all the variables

7x-20

Back to the equation:

-(7x-20)



We add all the numbers together, and all the variables

5x-(7x-20)-16=0

We get rid of parentheses

5x-7x+20-16=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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