2*(y+3)-3*(y-2)=-(2y-10)

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Solution for 2*(y+3)-3*(y-2)=-(2y-10) equation: 



2*(y+3)-3*(y-2)=-(2y-10)

We move all terms to the left:

2*(y+3)-3*(y-2)-(-(2y-10))=0

We multiply parentheses

2y-3y-(-(2y-10))+6+6=0



We calculate terms in parentheses: -(-(2y-10)), so:

-(2y-10)

We get rid of parentheses

-2y+10

Back to the equation:

-(-2y+10)



We add all the numbers together, and all the variables

-1y-(-2y+10)+12=0

We get rid of parentheses

-1y+2y-10+12=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2

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