2*5+z=29

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Solution for 2*5+z=29 equation: 



2*5+z=29

We move all terms to the left:

2*5+z-(29)=0

determiningTheFunctionDomain
z-29+2*5=0

We add all the numbers together, and all the variables

z-19=0

We move all terms containing z to the left, all other terms to the right

z=19

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