2*62+((62-2)/3)=n

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Solution for 2*62+((62-2)/3)=n equation:



2*62+((62-2)/3)=n
We move all terms to the left:
2*62+((62-2)/3)-(n)=0
We add all the numbers together, and all the variables
-n+2*62+(60/3)=0
We add all the numbers together, and all the variables
-1n+124+(60/3)=0
We get rid of parentheses
-1n+124+60/3=0
We multiply all the terms by the denominator
-1n*3+60+124*3=0
We add all the numbers together, and all the variables
-1n*3+432=0
Wy multiply elements
-3n+432=0
We move all terms containing n to the left, all other terms to the right
-3n=-432
n=-432/-3
n=+144

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