2*i*(-i)=2

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Solution for 2*i*(-i)=2 equation: 



2i(-i)=2

We move all terms to the left:

2i(-i)-(2)=0

We add all the numbers together, and all the variables

2i(-1i)-2=0

We multiply parentheses

-2i^2-2=0

a = -2; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-2)·(-2)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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